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Lake Ivanhoe, Wisconsin: Difference between revisions

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'''Lake Ivanhoe''' is a [[census-designated place]] in the town of [[Bloomfield, Walworth County, Wisconsin|Bloomfield]], [[Walworth County, Wisconsin|Walworth County]], [[Wisconsin]], [[United States]]. Its population was 435 as of the [[United States Census, 2010|2010 census]].<ref name=census>{{cite web|title=American FactFinder|url=http://factfinder2.census.gov/main.html|publisher=[[U.S. Census Bureau]]|accessdate=8 April 2011}}</ref>
'''Lake Ivanhoe''' is a [[census-designated place]] in the [[Bloomfield, Walworth County, Wisconsin|Town of Bloomfield]], [[Walworth County, Wisconsin|Walworth County]], [[Wisconsin]], [[United States]]. Its population was 435 as of the [[United States Census, 2010|2010 census]].<ref name=census>{{cite web|title=American FactFinder|url=http://factfinder2.census.gov/main.html|publisher=[[U.S. Census Bureau]]|accessdate=8 April 2011}}</ref>


==References==
==References==

Revision as of 01:08, 20 October 2015

Lake Ivanhoe, Wisconsin
CountryUnited States
StateWisconsin
CountyWalworth
Area
 • Total0.519 sq mi (1.34 km2)
 • Land0.519 sq mi (1.34 km2)
 • Water0 sq mi (0 km2)
Elevation
886 ft (270 m)
Population
 • Total435
 • Density840/sq mi (320/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code262
GNIS feature ID2586517[2]

Lake Ivanhoe is a census-designated place in the Town of Bloomfield, Walworth County, Wisconsin, United States. Its population was 435 as of the 2010 census.[1]

References

  1. ^ a b "American FactFinder". U.S. Census Bureau. Retrieved 8 April 2011.
  2. ^ U.S. Geological Survey Geographic Names Information System: Lake Ivanhoe, Wisconsin


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