Lake Ivanhoe, Wisconsin: Difference between revisions
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'''Lake Ivanhoe''' is a [[census-designated place]] in the [[Bloomfield, Walworth County, Wisconsin|Town of Bloomfield]], [[Walworth County, Wisconsin|Walworth County]], [[Wisconsin]], |
'''Lake Ivanhoe''' is a [[census-designated place]] in the [[Bloomfield, Walworth County, Wisconsin|Town of Bloomfield]], [[Walworth County, Wisconsin|Walworth County]], [[Wisconsin]], United States. Its population was 435 as of the [[United States Census, 2010|2010 census]].<ref name=census>{{cite web|title=American FactFinder|url=http://factfinder2.census.gov/main.html|publisher=[[U.S. Census Bureau]]|accessdate=8 April 2011}}</ref> |
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==References== |
==References== |
Revision as of 01:08, 15 January 2018
Lake Ivanhoe, Wisconsin | |
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Coordinates: 42°34′48″N 88°20′30″W / 42.58000°N 88.34167°W | |
Country | United States |
State | Wisconsin |
County | Walworth |
Area | |
• Total | 0.519 sq mi (1.34 km2) |
• Land | 0.519 sq mi (1.34 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 886 ft (270 m) |
Population | |
• Total | 435 |
• Density | 840/sq mi (320/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
Area code | 262 |
GNIS feature ID | 2586517[2] |
Lake Ivanhoe is a census-designated place in the Town of Bloomfield, Walworth County, Wisconsin, United States. Its population was 435 as of the 2010 census.[1]
References
- ^ a b "American FactFinder". U.S. Census Bureau. Retrieved 8 April 2011.
- ^ U.S. Geological Survey Geographic Names Information System: Lake Ivanhoe, Wisconsin