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Read more in the article [[Opaque pointer]].
Read more in the article [[Opaque pointer]].


Swapping of Variables without using Temporary Variables
'''Swapping of Variables without using Temporary Variables'''
''''''E-Mail Id: Saravanan029@gmail.com''''''
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Revision as of 11:30, 19 August 2011

A programming idiom is a means of expressing a recurring construct in one or more programming languages. Generally speaking, a programming idiom is an expression of a simple task or algorithm that is not a built-in feature in the programming language being used, or, conversely, the use of an unusual or notable feature that is built in to a programming language. The term can be used more broadly, however, to refer to complex algorithms or programming design patterns.

Knowing the idioms associated with a programming language and how to use them is an important part of gaining fluency in that language.

Examples of Simple Idioms

Incrementing a counter

In a language like BASIC, the code to increment a counter by one is mundane:

 i = i + 1

The C language, and many others derived from it, have language-specific features that make this code shorter:

 i += 1;  /* i = i + 1;  */
 ++i;     /* same result */
 i++;     /* same result */

There is a difference between the first two expressions, which yield the new version of i, and the third, which yields the old version of i. When the expressions are used as isolated statements, as in this example, the yielded value is ignored.

Pascal, as a keyword-centric language, contains a built in procedure for the same operation:

 i := i + 1;
 Inc(i); (* same *)

These are the idiomatic ways of "adding one to a counter".

Swapping values between variables

Main article: Swap (computer science)

In many languages, code for swapping the values in two variables looks like the following:

 temp = a;
 a = b;
 b = temp;

In Perl, the list assignment syntax allows a more succinct expression:

 ($a, $b) = ($b, $a);

Infinite loop

The code used to write an infinite (nonterminating) loop varies widely between different programming languages, although it often takes the form of a while loop where the test condition is always true. In Pascal, for example:

 while true do begin
   do_something();
 end;

There are several ways to write an infinite loop in C, including a loop very similar to the Pascal example, but the following idiom uses the unusual appearance of the empty for loop condition to draw attention visually to the loop:

 for (;;) {
   do_something();
 }

Perl allows the C syntax above, but supports some other syntax as well. For example:

 do_something() while (1);  # Succinct one-line infinite loop
 # same as
 while (1) { do_something() };

 # Using a "naked block" and the redo operator
 {
   do_something();
   redo;
 }

Ada loops forever this readable way:

 loop
   do_something;
 end loop;

Also readable python syntax:

   while True:
       do_something()

Array lookup hash table

Suppose we have an array of items, and we need to perform an operation in which we often need to determine whether some arbitrary item is in the array or not. Looking up an element in an array is an O(n) operation: we have to scan the array until we meet the element, or until the end.

Therefore, we create an associative array in which the array elements are keys, and the value is irrelevant. This assumes an implementation of associative arrays in which lookup is fast (e.g. hash tables, as in Perl).

The following idiom is commonly used to express this in Perl:

 my %elements = map { $_ => 1 } @elements;

Pimpl Idiom

In OOP the implementation details of a API-level class can be hidden in an own implementation class. A pointer (or reference) to that class is stored in the API-level class.

Read more in the article Opaque pointer.

Swapping of Variables without using Temporary Variables 'E-Mail Id: Saravanan029@gmail.com'


There are two types of solve the problem it is too simple.

First: By using (+ & -):-


       Dim a, b As Integer
       a = Val(TextBox1.Text)
       b = Val(TextBox2.Text)
       a = a + b
       b = a - b
       a = a - b
       TextBox3.Text = a
       TextBox4.Text = b

Second:By using (* & /):-


       Dim a, b As Integer
       a = Val(TextBox1.Text)
       b = Val(TextBox2.Text)
       a = a * b
       b = a / b
       a = a / b
       TextBox3.Text = a
       TextBox4.Text = b