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nLab Mercator series (changes)

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Contents

Idea

The “Mercator series” (so named after its appearance in Mercator 1667) is the Taylor series of the natural logarithm around 1.

Statement

\begin{proposition}\label{MercatorSeries} The Taylor series of the natural logarithm around 11 \in \mathbb{R} is the following series:

(1)n=01n!(d ndx nln(1+x)) |x=0x n =n=1(1) n+1nx n =x12x 2+13x 314x 4+. \begin{aligned} \underoverset{n = 0}{\infty}{\sum} \tfrac{1}{n!} \left( \frac{d^n}{ d x^n} ln(1 + x) \right)_{\vert x = 0} x^n & \;\; = \;\; \underoverset{n = 1}{\infty}{\sum} \frac {(-1)^{n+1}} {n} x^n \\ & \;\; = \;\; x - \tfrac{1}{2} x^2 + \tfrac{1}{3} x^3 - \tfrac{1}{4} x^4 + \cdots \,. \end{aligned}

\end{proposition} \begin{proof} For the first two terms notice that

ln(1+x)x0ln(1)=0 ln(1 + x) \;\xrightarrow{x \to 0}\; ln(1) \,=\, 0

and that the derivative of the natural logarithm is:

ddxln(1+x)=11+xx01. \frac{d}{d x} \ln(1 + x) \;=\; \tfrac{1}{1+x} \;\xrightarrow{ x \to 0 }\; 1 \,.

From here on, noticing for k +k \in \mathbb{N}_+ that:

ddx(1(1+x) k)=k1(1+x) k+1x0k \frac{d}{d x} \left( \frac{1}{(1 + x)^k} \right) \;=\; - k \frac{1}{(1 + x)^{k+1}} \;\xrightarrow{x \to 0}\; - k

we get, obtain forn +n \in \mathbb{N}_+, by induction:

d ndx nln(1+x) =d n1dx n1(11+x) =(n1)!(1) n11(1+x) n1 x0(n1)!(1) n+1. \begin{aligned} \frac{d^n}{d x^n} ln(1 + x) & \;=\; \frac{d^{n-1}}{d x^{n-1}} \left( \frac{1}{1 + x} \right) \\ & \;=\; (n-1)! \cdot (-1)^{n-1} \frac{1}{(1 + x)^{n-1}} \\ & \;\xrightarrow{ x \to 0 }\; (n-1)! \cdot (-1)^{n+1} \end{aligned} \,.

Plugging this into the defining equation on the left of (1) and using

(n1)!n!=1n \frac{(n-1)!}{n!} = \frac{1}{n}

yields the claim. \end{proof}

Note that this is not named for Gerardus Mercator, the cartographer with the famous map projection, but the mathematician Nicholas Mercator.

References

Apparently first published in:

but will have been known before that.

See also:

Last revised on July 25, 2021 at 07:40:01. See the history of this page for a list of all contributions to it.