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Lake Ivanhoe, Wisconsin: Difference between revisions

Coordinates: 42°34′48″N 88°20′30″W / 42.58000°N 88.34167°W / 42.58000; -88.34167
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{{Walworth County, Wisconsin}}
{{Walworth County, Wisconsin}}


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[[Category:Census-designated places in Walworth County, Wisconsin]]
[[Category:Census-designated places in Walworth County, Wisconsin]]

Revision as of 02:12, 13 February 2020

Lake Ivanhoe, Wisconsin
Lake Ivanhoe, Wisconsin is located in Wisconsin
Lake Ivanhoe, Wisconsin
Lake Ivanhoe, Wisconsin
Coordinates: 42°34′48″N 88°20′30″W / 42.58000°N 88.34167°W / 42.58000; -88.34167
CountryUnited States
StateWisconsin
CountyWalworth
Area
 • Total0.519 sq mi (1.34 km2)
 • Land0.519 sq mi (1.34 km2)
 • Water0 sq mi (0 km2)
Elevation
886 ft (270 m)
Population
 • Total435
 • Density840/sq mi (320/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code262
GNIS feature ID2586517[2]

Lake Ivanhoe is a census-designated place in the Town of Bloomfield, Walworth County, Wisconsin, United States. Its population was 435 as of the 2010 census.[1]

References

  1. ^ a b "American FactFinder". U.S. Census Bureau. Retrieved 8 April 2011.
  2. ^ U.S. Geological Survey Geographic Names Information System: Lake Ivanhoe, Wisconsin