OFFSET
1,2
COMMENTS
Christopher Hunt Gribble confirms a(3), and reports that there are 121 figures with group of order 1, 24 with group of order 2, and 4 with group of order 4. Then 121*(8/1) + 24*(8/2) + 4*(8/4) = 1072 = A003763(3), 121 + 24 + 4 = 149 = a(3). - N. J. A. Sloane, Feb 22 2013
REFERENCES
Jon Wild, Posting to Sequence Fans Mailing List, Dec 10 2011.
LINKS
Mathoverflow, Counting Hamiltonian cycles in n x n square grid, question asked by Joseph O'Rourke, Jul 25 2018.
Jon Wild, Illustration of a(3)
Ed Wynn, Enumeration of nonisomorphic Hamiltonian cycles on square grid graphs, arXiv:1402.0545 [math.CO], 3 Feb 2014.
CROSSREFS
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Mar 04 2012
EXTENSIONS
a(5)-a(10) from Ed Wynn, Feb 05 2014
STATUS
approved