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- _Gary W. Adamson, _, Jul 08 2011
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More generally, coefficients of (1+m*x-sqrt(m^2*x^2-(2*m+4)*x+1))/((2*m+2)*x) are given by: a(n) = sum(Sum_{k=0..n, } (m+1)^k*N(n,k)).
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a(0) = 1; , for n>=1, a(n) = sum(Sum_{k=0..n, } 9^k*N(n,k)), , where N(n,k) = (1/n)*C(n,k)*C(n,k+1) are the Narayana numbers (A001263).
1, 1
9, 9, 9
1, 1, 1, 1
9, 9, 9, 9, 9
1, 1, 1, 1, 1, 1
...
...
a(n) = (10*(2n2*n-1)*a(n-1) - 64*(n-2)*a(n-2)) / (n+1) for n>=2, a(0)=a(1)=1. - Philippe Deléham, Aug 19 2005
(Magma) [(&+[Binomial(n, k)*Binomial(n-1, k)*9^k/(k+1): k in [0..n]]): n in [0..30]]; // G. C. Greubel, May 23 2022
(SageMath) [sum(binomial(n, k)*binomial(n-1, k)*9^k/(k+1) for k in (0..n)) for n in (0..30)] # G. C. Greubel, May 23 2022
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